x^2+40x-460=0

Solution for x^2+40x-460=0 equation:

x^2+40x-460=0

a = 1; b = 40; c = -460;
Δ = b2-4ac
Δ = 402-4·1·(-460)
Δ = 3440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3440}=\sqrt{16*215}=\sqrt{16}*\sqrt{215}=4\sqrt{215}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{215}}{2*1}=\frac{-40-4\sqrt{215}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{215}}{2*1}=\frac{-40+4\sqrt{215}}{2}
$